Please help me solve this problem by coming up with a linear algebra equation:
A biathlon event involves running and cycling. Kim can cycle 30km/h faster than she can run If Kim spends 48 minutes and a third as much time again cycling in an event that covers a total distance of 60 km, how fast can she run?
Formula: distance= speed * time
Hi delicate_tears,
Let's see if I'm interpreting this problem correctly.
Let x = speed in km/h running
Let x + 30 = speed in km/hr cycling
48 minutes running = 48/60 = 4/5 hours
one-third as much again cycling seems like 48 + 1/3(48) = 64 minutes = 64/60 = 16/15 hours.
d = rate X time
d = 60
The distance traveled while running would be
The distance traveled while cycling would be
The two distances together would equal 60 km.
The linear equation would then be:
Hey Leona_Marie, thanks for replying first to my thread! Unfortunately I don't quite understand the equation you wrote as it contained too many slashes that I got mixed up.
Hi masters, my interpretation of the problem is different to yours but your interpretation is actually the correct one.
Where the word problem says 'as third as much time again cycling' I wrote is as 1/3(48)= 16 minutes= 16/60 hr = 4/15 hr.
Thankyou so much