Please help me solve this problem by coming up with a linear algebra equation:
A biathlon event involves running and cycling. Kim can cycle 30km/h faster than she can run If Kim spends 48 minutes and a third as much time again cycling in an event that covers a total distance of 60 km, how fast can she run?
Formula: distance= speed * time
Let's see if I'm interpreting this problem correctly.
Let x = speed in km/h running
Let x + 30 = speed in km/hr cycling
48 minutes running = 48/60 = 4/5 hours
one-third as much again cycling seems like 48 + 1/3(48) = 64 minutes = 64/60 = 16/15 hours.
d = rate X time
d = 60
The distance traveled while running would be
The distance traveled while cycling would be
The two distances together would equal 60 km.
The linear equation would then be:
Hey Leona_Marie, thanks for replying first to my thread! Unfortunately I don't quite understand the equation you wrote as it contained too many slashes that I got mixed up.
Where the word problem says 'as third as much time again cycling' I wrote is as 1/3(48)= 16 minutes= 16/60 hr = 4/15 hr.
Thankyou so much