This problem confuses me:

1. $\displaystyle \frac{32c^3d^3}{64c^2d}$

I know how to reduce these two:

4. $\displaystyle \frac{2x+6}{3ax+9a}=\frac{2(x+3)}{3a(x+3)}=\frac{2 }{3a} $

9. $\displaystyle \frac{y^2+2y-15}{2y^2-12y+18}=\frac{(y-3)(y+5)}{(y-3)(2y-6)}=\frac{y+5}{2y-6}$

but how can I do that process when there is only one term in the numerator and denominator, like number 1??