1. ## Simplifying

I'm having trouble simplifying this equation

2. Originally Posted by casey_k
I'm having trouble simplifying this equation
note that you have:

$\frac {x^2 - 4xy + 4y^2}{x^2 - y^2} \times \frac {x^2 + 2xy + y^2}{x^2 + xy - 6y^2}$

$= \frac {(x - 2y)^2}{(x + y)(x - y)} \times \frac {(x + y)^2}{x^2 + xy - 6y^2}$

can you take it from here?

3. $\frac {x^2-4xy+4y^2}{x^2-y^2}$ $/ \frac {x^2 + xy - 6y^2}{x^2+2xy+y^2}$

$= \frac {(x-2y)^2}{(x+y)(x-y)} / \frac {(x+3y)(x-2y)}{(x+y)^2}$

$=\frac {(x-2y)^2}{(x+y)(x-y)} * \frac {(x+y)^2}{(x+3y)(x-2y)}$

$= \frac {(x-2y)(x+y)}{(x-y)(x+3y)}$

$= \frac {x^2-xy-2y^2}{x^2+2xy+3y^2}$

4. Oh, Sorry, Jhevon I did not notice you had posted while I was typing the solution.

5. yea, i can take it from here. thank you so much for making the problem more clearer!

6. Originally Posted by muks
Oh, Sorry, Jhevon I did not notice you had posted while I was typing the solution.
don't worry about it. you did a better job than i did. i didn't factorize the $x^2 + xy - 6y^2$