If a:b=3:5, find the value of $\displaystyle \dfrac{a}{\sqrt{b^2-a^2}}$

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- Jan 22nd 2009, 08:37 PMrequalRatios/equations
If a:b=3:5, find the value of $\displaystyle \dfrac{a}{\sqrt{b^2-a^2}}$

- Jan 22nd 2009, 09:35 PMJhevon
- Jan 22nd 2009, 11:26 PMrequal
i dont think that works as (3/5b)^2 is larger than b^2 thus creating a negative number under a square root?(Wondering)

- Jan 23rd 2009, 12:13 AMJhevon
- Jan 23rd 2009, 02:36 AMrequal
yep, sorry I had mental diaharea(Crying) thanks anyway