Is y^2 = 4 - x^2 the same as:
y= 2 - x
OR
y= (4 - x^2)/y
Thank you!
Hi RB89,
If you're wanting to solve for y, you will need to take the square root of both sides of the equation.
$\displaystyle y^2=4-x^2$
$\displaystyle y=\sqrt{4-x^2}$
And that's about it.
Now, if you had something like: $\displaystyle y^2=4x^2$, you could get to $\displaystyle y=2x$ because the right side of the equation was a perfect square. That wasn't the case in your example.