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Math Help - Help with algebra

  1. #1
    Newbie
    Joined
    Feb 2008
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    8

    Help with algebra

    Hey guys/gals i am doing this equation and am stuck at this point

    (bx) - ((ap-a^2x)/b)

    i don't even know where to start

    thanks

    Josh
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  2. #2
    MHF Contributor
    Joined
    Sep 2008
    From
    West Malaysia
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    1,261

    RE :

    Quote Originally Posted by sinners View Post
    Hey guys/gals i am doing this equation and am stuck at this point

    (bx) - ((ap-a^2x)/b)

    i don't even know where to start

    thanks

    Josh

    Did u mean this .. bx-\frac{ap-a^2x}{b}

    What are you trying to find ? Simplify ?
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  3. #3
    Newbie
    Joined
    Feb 2008
    Posts
    8
    yes soz i forgot the last part all of that equals q, solve for x

    thanks

    Josh
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  4. #4
    MHF Contributor
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    Sep 2008
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    West Malaysia
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    Re :

    bx-\frac{ap-a^2x}{b}=q

    \frac{b^2x-ap+a^2x}{b}=q

    b^2x+a^2x=bq+ap

    (b^2+a^2)x=bq+ap

    x=\frac{bq+ap}{b^2+a^2}
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