1. ## Help with algebra

Hey guys/gals i am doing this equation and am stuck at this point

(bx) - ((ap-a^2x)/b)

i don't even know where to start

thanks

Josh

2. ## RE :

Originally Posted by sinners
Hey guys/gals i am doing this equation and am stuck at this point

(bx) - ((ap-a^2x)/b)

i don't even know where to start

thanks

Josh

Did u mean this .. $bx-\frac{ap-a^2x}{b}$

What are you trying to find ? Simplify ?

3. yes soz i forgot the last part all of that equals q, solve for x

thanks

Josh

4. ## Re :

$bx-\frac{ap-a^2x}{b}=q$

$\frac{b^2x-ap+a^2x}{b}=q$

$b^2x+a^2x=bq+ap$

$(b^2+a^2)x=bq+ap$

$x=\frac{bq+ap}{b^2+a^2}$