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Math Help - Equations - Can't solve it!

  1. #1
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    Equations - Can't solve it!

    Here's the thing:

     <br />
\frac{3}{x-3}-\frac{1}{2x-6}=\frac{5}{6}<br />

    For this to add up, I need the bottom(?) to be the same, but how can I do that?
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  2. #2
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    Hello,
    Quote Originally Posted by Pingu View Post
    Here's the thing:

     <br />
\frac{3}{x-3}-\frac{1}{2x-6}=\frac{5}{6}<br />

    For this to add up, I need the bottom(?) to be the same, but how can I do that?
    Note that 2x-6=2(x-3)

    So \frac{3}{x-3}-\frac{1}{2x-6}=\frac{3}{x-3}-\frac{1/2}{x-3}
    And this easily adds up


    In general, it's not that simple, you have to multiply both fractions by a factor such that the denominator becomes the highest common factor between the denominators.
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  3. #3
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    Maybe you should do it like this.

    <br />
\frac{6*3}{6(x-3)}-\frac{3*1}{3*2(x-3)}=\frac{5(x-3)}{6(x-3)}<br />
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  4. #4
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    Quote Originally Posted by Pingu View Post
    Here's the thing:

     <br />
\frac{3}{x-3}-\frac{1}{2x-6}=\frac{5}{6}<br />

    For this to add up, I need the bottom(?) to be the same, but how can I do that?
    you should factor  2x-6 first to get the common factor

     \frac{2(x-3)}{x-3}

    so the common factor is  x-3


     \frac{3}{x-3}-\frac{1}{2x-6}=\frac{5}{6}

     \frac{3*2}{2(x-3)}-\frac{1}{2x-6}=\frac{5}{6}

     \frac{6}{2x-6}-\frac{1}{2x-6}=\frac{5}{6}

     \frac{5}{2x-6}=\frac{5}{6}

     5(6)=5(2x-6)

     30=10x-30

     60=10x

     x=6

    Last edited by princess_21; January 22nd 2009 at 03:43 AM.
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