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Math Help - Coin Problem

  1. #1
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    Coin Problem

    The value (in cents) of the change in a purse that contains twice as many nickels as pennies, four more dimes than nickels, and as many quarters as dimes and nickels combined; p = number of pennies
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  2. #2
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    p=number of pennies

    2 times the number of pennies is how many nickels there are... nickels are 5 pennies though.

    4 more dimes than nickels (there are (2p) nickels), and dimes are 10 times more than p.

    the total number of dimes and nickels is 2p and 2p+4 .... but a quarter is 25 times that..

    Don't hate me if I'm wrong.. this is complicated but, I believe the equation works out:


    p + (2(5p)) + ((2p+4)*10) + (25*(2p+2p+4))

    simplify.
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  3. #3
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    that worked out great thanks alot for the help.
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