The value (in cents) of the change in a purse that contains twice as many nickels as pennies, four more dimes than nickels, and as many quarters as dimes and nickels combined;p= number of pennies

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- Jan 20th 2009, 04:48 PMtmac11522Coin Problem
The value (in cents) of the change in a purse that contains twice as many nickels as pennies, four more dimes than nickels, and as many quarters as dimes and nickels combined;

*p*= number of pennies - Jan 20th 2009, 04:57 PMmike_302
p=number of pennies

2 times the number of pennies is how many nickels there are... nickels are 5 pennies though.

4 more dimes than nickels (there are (2p) nickels), and dimes are 10 times more than p.

the total number of dimes and nickels is 2p and 2p+4 .... but a quarter is 25 times that..

Don't hate me if I'm wrong.. this is complicated but, I believe the equation works out:

p + (2(5p)) + ((2p+4)*10) + (25*(2p+2p+4))

simplify. - Jan 20th 2009, 05:03 PMtmac11522
that worked out great thanks alot for the help.