1. ## algebra problem

help me.....im stupid.....

redical x^2 - y^2 = 6

the answer is x=10 & y=8 .......................but how can i get it..............thnx

2. Hi

I suppose that x and y are integers
$\displaystyle \sqrt{x^2-y^2} = 6$
$\displaystyle x^2-y^2 = 36$
$\displaystyle (x-y)(x+y) = 36 = 2^2 \cdot 3^2$

(x-y) being smaller than (x+y) the possibilities for ((x-y),(x+y)) are (1,36) ; (2,18) ; (3,12) ; (4;9) ; (6;6)
Their sum must be even because (x-y)+(x+y)=2x
Remain 2 possibilities
(2,18) => x=10 and y=8
(6,6) => x=6 and y=0