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Math Help - Due tommorrow problem solving!!

  1. #1
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    Due tommorrow problem solving!!

    1. Albert has $2.70 more than Bert does. Bert Has three times as much money as Chris does. Together, the three friends have $26.22. How much money does Albert have?

    2. A square based pyrapid has a volume of 12a^5b^4 units^3 and has a height of 9a^3 units. Determine the side length of the base.

    ****BTW.. when i was trying #2, I had to use the volume of square based pyramid. If you dont wanna look it up, it is:

    V=2bs+b^2*****

    ****Another BTW.. if you dont know already, ^=Exponent**** Thanks a million!



    IN URGENT HURRY! PLEASE!! DESPERATE!!!!
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  2. #2
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    Quote Originally Posted by princevisram View Post
    1. Albert has $2.70 more than Bert does. Bert Has three times as much money as Chris does. Together, the three friends have $26.22. How much money does Albert have?

    2. A square based pyrapid has a volume of 12a^5b^4 units^3 and has a height of 9a^3 units. Determine the side length of the base.

    ****BTW.. when i was trying #2, I had to use the volume of square based pyramid. If you dont wanna look it up, it is:

    V=2bs+b^2*****

    ****Another BTW.. if you dont know already, ^=Exponent**** Thanks a million!



    IN URGENT HURRY! PLEASE!! DESPERATE!!!!
    1. See if you can follow where I got these equations from...

    A = B + 2.70

    B = 3C so therefore A = 3C + 2.70.


    A + B + C = 26.22

    3C + 2.70 + 3C + C = 26.22.


    Solve for C, then you can work out B and A.
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  3. #3
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    Thanks but...?

    Okay.. Thank you... but would this be the rest of the question?::

    3C+2.70+3C+C=26.22
    7C+2.70=26.22
    7C=26.22-2.70
    7C=23.52
    7C/7=23.52/7
    C=3.36
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  4. #4
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    Quote Originally Posted by princevisram View Post
    Okay.. Thank you... but would this be the rest of the question?::

    3C+2.70+3C+C=26.22
    7C+2.70=26.22
    7C=26.22-2.70
    7C=23.52
    7C/7=23.52/7
    C=3.36
    What do A and B equal?
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    Quote Originally Posted by Prove It View Post
    What do A and B equal?

    Okay.. So..

    Now, Find B

    B=3C
    B=3(3.36)
    B=10.08

    Now, Find A

    A=B+2.70
    A=10.08+2.70
    A=12.78

    Right? If so, can you please help me w/#2? Thank you sooooo much for your help! This site ROXX!
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  6. #6
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    Quote Originally Posted by princevisram View Post
    1. Albert has $2.70 more than Bert does. Bert Has three times as much money as Chris does. Together, the three friends have $26.22. How much money does Albert have?

    2. A square based pyrapid has a volume of 12a^5b^4 units^3 and has a height of 9a^3 units. Determine the side length of the base.

    ****BTW.. when i was trying #2, I had to use the volume of square based pyramid. If you dont wanna look it up, it is:

    V=2bs+b^2*****

    ****Another BTW.. if you dont know already, ^=Exponent**** Thanks a million!



    IN URGENT HURRY! PLEASE!! DESPERATE!!!!
    Yes it's correct.

    For 2. Are you sure you've written down the volume correctly?
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  7. #7
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    Quote Originally Posted by princevisram View Post
    [snip]
    2. A square based pyrapid has a volume of 12a^5b^4 units^3 and has a height of 9a^3 units. Determine the side length of the base.
    [snip]
    Is that 12a^5b^4 and 9a^3 respectively?

    It helps if you learn LaTeX so I can read it...
    Last edited by mr fantastic; January 18th 2009 at 10:40 PM. Reason: Trying to fix up this thread
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    Quote Originally Posted by Prove It View Post
    Is that 12a^5b^4 and 9a^3 respectively?

    It helps if you learn LaTeX so I can read it...

    yess!! Thankss! Thats my question! Now can you help me solve it please???! Thanks soo much! PS where can i learn LaTeX?
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    Quote Originally Posted by princevisram View Post
    yess!! Thankss! Thats my question! Now can you help me solve it please???! Thanks soo much! PS where can i learn LaTeX?
    There are lots of online tutorials and help guides in the LaTeX sub forum here.

    Ok, first off, the formula for the volume of a square based pyramid is

    V = l^2H where l is the side length of the square and H is the height of the pyramid.

    You're told H = 9a^3 and V = 12a^5b^4.


    Using these bits of information we get

    12a^5b^4 = l^2(9a^3).

    Solve for l.
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    Quote Originally Posted by Prove It View Post
    There are lots of online tutorials and help guides in the LaTeX sub forum here.

    Ok, first off, the formula for the volume of a square based pyramid is

    V = l^2H where l is the side length of the square and H is the height of the pyramid.

    You're told H = 9a^3 and V = 12a^5b^4.


    Using these bits of information we get

    12a^5b^4 = l^2(9a^3).

    Solve for l.
    I understand to where you are, but i totaly dont understand how to solve for l.
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  11. #11
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    Quote Originally Posted by princevisram View Post
    I understand to where you are, but i totaly dont understand how to solve for l.
    Divide by 9a^3, simplify, then take the square root.
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    Quote Originally Posted by Prove It View Post
    Divide by 9a^3, simplify, then take the square root.
    Oh my goshh!! I totaly dont understand...! Im sorry..
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  13. #13
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    Quote Originally Posted by princevisram View Post
    Oh my goshh!! I totaly dont understand...! Im sorry..
    Think about it like this...

    What's happened to l to turn it into 12a^5b^4.

    It's been squared, then multiplied by 9a^3.


    So to undo all this stuff that's happened, we do the inverse operations in reverse order.

    What's the opposite of multiplying by 9a^3?

    What's the opposite of squaring?
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    Quote Originally Posted by Prove It View Post
    Think about it like this...

    What's happened to l to turn it into 12a^5b^4.

    It's been squared, then multiplied by 9a^3.


    So to undo all this stuff that's happened, we do the inverse operations in reverse order.

    What's the opposite of multiplying by 9a^3?

    What's the opposite of squaring?
    would it be:

    12a^5b^4 = l^2\div9a^3.

    ???
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  15. #15
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    Quote Originally Posted by princevisram View Post
    would it be:

    12a^5b^4 = l^2/9a^3.

    ??? / being diveded by
    No.

    We have

    l^2(9a^3) = 12a^5b^4.

    Divide BOTH sides by 9a^3.

    We then have

    l^2 = \frac{12a^5b^4}{9a^3}

    l^2 = \frac{4a^2b^4}{3}.

    Now take the square root of both sides to get l.

    l = \sqrt{\frac{4a^2b^4}{3}}

     = \frac{2ab^2}{\sqrt{3}}

     = \frac{2\sqrt{3}ab^2}{3}.
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