Thread: algebraic expressions

What is the proper way to work this probelm...4cd =14...c=1/2d=7
What is the right way to wok this problem ?

Originally Posted by Leona_Marie

What is the proper way to work this probelm...4cd =14...c=1/2d=7
What is the right way to wok this problem ?

the way i would solve it is by just replacing what we all ready know.

4(c)(d)=14 c=1 d=7/2=3.5

4(1)(3.5)=14

hope that helps.

What is the proper way to work this probelm...4cd =14...c=1/2d=7
What is the right way to wok this problem ?

yup darkness9375 is right
there are 1 equation and 2 unknown variable
we have to assume 1 variable to get the value of another variable

Originally Posted by darkness9375

the way i would solve it is by just replacing what we all ready know.

4(c)(d)=14 c=1 d=7/2=3.5

4(1)(3.5)=14

hope that helps.

could you break it down to me like...
4(c)(d)
4(1)(d)
4(1)(7/2)
How did you get 1/2 to =1 and why are you x 7/2 and afterwards how are you x3.5 to get =14 I thought 4x7 is 28 -1/2=14

Originally Posted by ursa

yup darkness9375 is right
there are 1 equation and 2 unknown variable
we have to assume 1 variable to get the value of another variable

Ursa when using frac, with algebra...1st equation is 4 sec is 1/2 which is(c)third is7 or(d). So 1/2 x7/1=1x7and2x1=7/2. 2divided by 7=3 1/2=3.5...3.5x4=14 yes???

Originally Posted by Leona_Marie

What is the proper way to work this probelm...4cd =14...c=1/2d=7
What is the right way to wok this problem ?

Hi Leona,

I'm not sure that you have stated your question properly. Try and be a little clearer. Use parentheses, separate lines, anything to set apart what it is you are trying to convey.

Looks like your original equation is

Then, the second part is ambiguous.

Dose and does ?

If that's the case, then substitute 7 for c and solve for d. But I'm not sure that's the case.

Originally Posted by masters

Hi Leona,

I'm not sure that you have stated your question properly. Try and be a little clearer. Use parentheses, separate lines, anything to set apart what it is you are trying to convey.

Looks like your original equation is

Then, the second part is ambiguous.

Dose and does ?

If that's the case, then substitute 7 for c and solve for d. But I'm not sure that's the case.

4cd is the equation Im not sure how to use (c) which =1/2 to get the answer =14 Im guessing you x (c) which=1/2 x (d) which =7 . I just thought that you would use multiplying fractions ...1/2 x7/1 =3.5. 3.5 x 4 =14 4cd =14 please varify or change leona

Originally Posted by Leona_Marie

4cd=14 is the equation Im not sure how to use (c) which =1/2 to get the answer =14 Im guessing you x (c) which=1/2 x (d) which =7 . I just thought that you would use multiplying fractions ...1/2 x7/1 =3.5. 3.5 x 4 =14 4cd =14 please varify or change leona

Ok, Leona, I think you intend to state the problem this way.





Substituting, we get









Checking, we substitute the values we found for c and d back into the original equation and get:

Originally Posted by masters

Ok, Leona, I think you intend to state the problem this way.





Substituting, we get









Checking, we substitute the values we found for c and d back into the original equation and get:

Thanks p.s how do you give thanks

Originally Posted by Leona_Marie

Thanks p.s how do you give thanks

Click on the "Thanks" button below the post.