6x(to the power of 2) + 42x=0

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- Jan 18th 2009, 05:36 PMleanncollege algebra
6x(to the power of 2) + 42x=0

- Jan 18th 2009, 05:39 PMo_O
Factor out a$\displaystyle 6x$.

$\displaystyle \begin{aligned} 6x^2 + 42x & = 0 \\ 6x(x + 7) & = 0 \end{aligned}$

Now note that if two numbers multiplied together equals to 0, then either one or both of the numbers**are**0. So let's set both factors (6x and the x + 7) equal to 0 to see what we get.

$\displaystyle 6x = 0 \qquad x + 7 = 0$

Can you carry on from here?