solve the following by factoring: im so lost on this please help!!! x(to the power of 2) - 6x - 16 =0
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See if you can follow the example here: Tips on factoring, a not equal to 1 The process is exactly the same for any quadratic.
Originally Posted by leann solve the following by factoring: im so lost on this please help!!! x(to the power of 2) - 6x - 16 =0 $\displaystyle x^2-6x-16=0$ $\displaystyle (x-8)(x+2)$ you can check by foiling $\displaystyle x^2+2x-8x-16=x^2-6x-16$ $\displaystyle x-8=0$ and $\displaystyle x+2=0$ $\displaystyle x=8 $ and $\displaystyle x=-2$ is the solution
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