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Math Help - dividing fractions

  1. #1
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    Talking dividing fractions

    i got lost in complex fractions. i don't know how to input equations here..
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    Wink

    {1 - [1/(m-1)] }/ {1+ [1/(m-1)]} + {1- [1/(1+(1/(m-1)]}/ {1-[1/(1-1/(m-1)}

    is it stilll unclear?
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  3. #3
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    You could let 1=\frac{m-1}{m-1} see if that helps.
    Last edited by ronaldo_07; January 16th 2009 at 11:26 PM.
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  4. #4
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    Fractions

    Hello princess_21
    Quote Originally Posted by princess_21 View Post
    i got lost in complex fractions. i don't know how to input equations here..
    Sorry, I can't understand your attached document. But have another look at the one you've already visited

    http://www.mathhelpforum.com/math-he...fractions.html

    If you're still really stuck, can you write one out neatly by hand, and either scan it or take a digital photo, and attach that instead?

    Grandad
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by princess_21 View Post
    {1 - [1/(m-1)] }/ {1+ [1/(m-1)]} + {1- [1/(1+(1/(m-1)]}/ {1-[1/(1-1/(m-1)}

    is it stilll unclear?
    is this it?

    \displaystyle \frac {1 - \frac 1{m - 1}}{1 + \frac 1{m - 1}} + \frac {1 - \frac 1{1 + \frac 1{m - 1}}}{1 - \frac 1{1 - \frac 1{m-1}}}
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  6. #6
    Member ronaldo_07's Avatar
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    Quote Originally Posted by princess_21 View Post
    {1 - [1/(m-1)] }/ {1+ [1/(m-1)]} + {1- [1/(1+(1/(m-1)]}/ {1-[1/(1-1/(m-1)}

    is it stilll unclear?
    \frac{1-\frac{1}{m-1}}{1+\frac{1}{m-1}}+\frac{1-\frac{1}{1+\frac{1}{m-1}}}{1-\frac{1}{1-\frac{1}{m-1}}}

    Is this the correct equation?
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  7. #7
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ronaldo_07 View Post
    \frac{1-\frac{1}{m-1}}{1+\frac{1}{m-1}}+\frac{1-\frac{1}{1+\frac{1}{m-1}}}{1-\frac{1}{1-\frac{1}{m-1}}}

    Is this the correct equation?
    haha, well, both you and i interpreted it the same way. chances are we're correct...unless there was a typo.

    would you like to proceed?
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  8. #8
    Member ronaldo_07's Avatar
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    Quote Originally Posted by ronaldo_07 View Post
    You could let 1=\frac{m-1}{m-1} see if that helps.
    I would let 1-\frac{1}{m-1}=\frac{m-1}{m-1}-\frac{1}{m-1}

    This simplyfies to (m-2)

    Do this also for 1+\frac{1}{m-1} and it should come in a nice form for you to easily work out m
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    Red face

    here's another attachment..
    Attached Thumbnails Attached Thumbnails dividing fractions-picture-69.jpg  
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    Thumbs up

    yeah. that's the question. thanks
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  11. #11
    Member ronaldo_07's Avatar
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    Quote Originally Posted by princess_21 View Post
    here's another attachment..
    We have interpreted correctly look above for help I have provided
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  12. #12
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    Lightbulb

    Quote Originally Posted by Jhevon View Post
    haha, well, both you and i interpreted it the same way. chances are we're correct...unless there was a typo.

    would you like to proceed?

    yeah that's the question..
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  13. #13
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    i solved it this way.
    let m= m-1

    and then i got (2m-2)/(m+1)... is this correct?
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  14. #14
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by ronaldo_07 View Post
    I would let 1-\frac{1}{m-1}=\frac{m-1}{m-1}-\frac{1}{m-1}

    This simplyfies to (m-2)

    Do this also for 1+\frac{1}{m-1} and it should come in a nice form for you to easily work out m
    indeed. just to flesh it out a bit

    \displaystyle \frac {1 - \frac 1{m - 1}}{1 + \frac 1{m - 1}} \cdot {\color{red} \frac {m - 1}{m - 1}} + \frac {1 - \frac 1{1 + \frac 1{m - 1}} \cdot {\color{red} \frac {m - 1}{m - 1}}}{1 - \frac 1{1 - \frac 1{m-1}} \cdot {\color{red} \frac {m - 1}{m - 1}}}

    = \frac {m - 1 - 1}{m - 1 + 1} + \frac {1 - \frac {m - 1}{m - 1 + 1}}{1 - \frac {m - 1}{m - 1 - 1}}

    = \frac {m - 2}m + \frac {1 - \frac {m - 1}m}{1 - \frac {m - 1}{m - 2}}

    now perform a similar trick on the second fraction as i did before and continue
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by princess_21 View Post
    i solved it this way.
    let m= m-1

    and then i got (2m-2)/(m+1)... is this correct?
    you cannot solve it that way. you would be changing the value of the fraction. you would have to use another variable and then make the back-substitution afterwards. just follow the trick you have been shown. it is the easiest way
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