Hello, Lupin!
Can anyone tell me how to solve an inequality like this?
$\displaystyle x^2+x6\:<\:0$.
I tried factorising it like this: .$\displaystyle (x+3)(x2)\:<\:0$
But I don't see how I can solve it from there.
We have a parabola: .$\displaystyle y \:=\:x^2 + x  6 \:=\:(x+3)(x2)$
It opens upward and has xintercepts 3 and 2.
So it looks like this: Code:

*  *

*  *
  *    +  *     
3 *  * 2
* 

And they are asking: When is the function negative?
. . That is: When is the parabola below the xaxis?
Got it?