# Math Help - Quadratic Equation

I am in need of some assistance, thanks!

f (x) = 2 - (x - 3)^2 .

(a) I need to write this function in the general form of a quadratic equation ax^2 + bx + c

$
f(x) = 2 - (x-3)(x-3)
= 2- x^2-3x-3x+9
= 2 - x^2-6x+9
= -x^2-6x+11
$

Can anyone double check this for me, please?

2. Originally Posted by studentme
I am in need of some assistance, thanks!

f (x) = 2 - (x - 3)^2 .

(a) I need to write this function in the general form of a quadratic equation ax^2 + bx + c

$
f(x) = 2 - (x-3)(x-3)
= 2- x^2-3x-3x+9
= 2 - x^2-6x+9
= -x^2-6x+11
$

Can anyone double check this for me, please?
$
f(x) = 2 - (x-3)(x-3)
= 2 - (x^2-6x+9)
= -x^2+6x-7
$

3. Originally Posted by studentme
$
f(x) = 2 - (x-3)(x-3)
= 2 - x^2-3x-3x+9
= 2 - x^2-6x+9
= -x^2-6x+11
$

${2 - x^2-3x-3x+9} \neq 2 - (x^2-3x-3x+9)$... This is why parantheses are so important!