I am in need of some assistance, thanks!

f (x) = 2 - (x - 3)^2 .

(a) I need to write this function in the general form of a quadratic equation ax^2 + bx + c

The answer I got:

$\displaystyle

f(x) = 2 - (x-3)(x-3)

= 2- x^2-3x-3x+9

= 2 - x^2-6x+9

= -x^2-6x+11

$

Can anyone double check this for me, please?