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Math Help - Quadratic Equation

  1. #1
    Newbie
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    Quadratic Equation

    I am in need of some assistance, thanks!

    f (x) = 2 - (x - 3)^2 .

    (a) I need to write this function in the general form of a quadratic equation ax^2 + bx + c

    The answer I got:

    <br />
f(x) = 2 - (x-3)(x-3)<br />
= 2- x^2-3x-3x+9<br />
= 2 - x^2-6x+9<br />
= -x^2-6x+11<br />

    Can anyone double check this for me, please?
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  2. #2
    Member Last_Singularity's Avatar
    Joined
    Dec 2008
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    Quote Originally Posted by studentme View Post
    I am in need of some assistance, thanks!

    f (x) = 2 - (x - 3)^2 .

    (a) I need to write this function in the general form of a quadratic equation ax^2 + bx + c

    The answer I got:

    <br />
f(x) = 2 - (x-3)(x-3)<br />
= 2- x^2-3x-3x+9<br />
= 2 - x^2-6x+9<br />
= -x^2-6x+11<br />

    Can anyone double check this for me, please?
    <br />
f(x) = 2 - (x-3)(x-3)<br />
= 2 - (x^2-6x+9)<br />
= -x^2+6x-7<br />
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  3. #3
    Lord of certain Rings
    Isomorphism's Avatar
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    IISc, Bangalore
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    Quote Originally Posted by studentme View Post
    <br />
f(x) = 2 - (x-3)(x-3)<br />
= 2 - x^2-3x-3x+9<br />
= 2 - x^2-6x+9<br />
= -x^2-6x+11<br />
    {2 - x^2-3x-3x+9} \neq 2 - (x^2-3x-3x+9) ... This is why parantheses are so important!
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