remainder theorem ... if the remainder is 2/(2x+1), then f(-1/2) = 2
4(-1/2)^4 - 15(-1/2)^2 + p(-1/2) + 6 = 2
1/4 - 15/4 - p/2 + 6 = 2
-7/2 + 8/2 = p/2
1 = p
4x^4 - 15x^2 + px + 6 / 2x+1 gives remainder 2/2x+1 .... Solve for p
My method in reviewing was to synthetically divide, and begin filling in what I could until p was surrounded, then I told it to put its hand up and surrender... It gave in, and I got the answer of 1.
But I did a test that had a slightly different question to it, but still a "solve for p" and I did it differently.. In that case, I was given a factor of the polynomial, and so I subbed it in to the equation (when that factor equalled zero) and set it all equal to zero... solved for p.
I just have a feeling there is a different way I could have done it here in the review...