Evaluate exactly:

a. $\displaystyle

\sum_{k=1}^{100} (1 + (-1)^k)

$

b. $\displaystyle

\sum_{k=3}^{6} \frac{k^2+2}{k-2}

$

For these above do I just plug in the values within the interval into k and then add the total?

so forbwould it be:

$\displaystyle

\frac{3^2 + 2}{3 - 2} + \frac{4^2 + 2}{4 - 2} + \frac{5^2 + 2}{5 - 2} + \frac{6^2 + 2}{6 - 2} = 11 + 9 + 9 + 9.5 = 38.5$

Is this correct or am I way off? haha

Thank you to anyone who attempts this for me : )