Thread: Solving equation involving e and ln

Solve lnx + ln(x-3) = 0

So far my working is

e^(lnx) + e^(ln(x-3)) = e^0

x + (x-3) = 1

and so on

But this leads me to the incorrect solution. Where did I go wrong?

Originally Posted by hymnseeker

e^(lnx) + e^(ln(x-3)) = e^0

Where did I go wrong?

You can't do what you did.
What you can do is

How foolish of me to miss that.

Thanks again.

Originally Posted by hymnseeker

Solve lnx + ln(x-3) = 0

So far my working is

e^(lnx) + e^(ln(x-3)) = e^0

x + (x-3) = 1

and so on

But this leads me to the incorrect solution. Where did I go wrong?

Hello hymnseeker,

Try this: