Ok just quickly what happens in this case A + B = 3 -2A - 2B = -2 Both terms disapear when I add them together.. what do i need to do to get the values of A and B?? 2A +2B = 6 -2A -2B = -2 0 = 4
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What was the original question? Divide the second equation by -2 and we have: Now think about this logically. How can two numbers add up to 3 and 1 at the same time?
I see... I was doing partial fractions, int (3-2x) / (x^2-4x+4) int (3-2x) / (x-2)(x-2) A(x-2)+B(x-2) Numerator: (A+B)x + (-2A-2B) I'm guessing I've done something wrong here..
You have to combine the linear factors in the denominator into a single power: Then apply partial fraction decomposition: Try it now.
Ah right I get it, thanks alot!!
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