Ok just quickly what happens in this case
A + B = 3
-2A - 2B = -2
Both terms disapear when I add them together.. what do i need to do to get the values of A and B??
2A +2B = 6
-2A -2B = -2
0 = 4
You have to combine the linear factors in the denominator into a single power: $\displaystyle \int \frac{3-2x}{x^2 - 4x + 4} \ dx = \int \frac{3-2x}{(x-2)^2} \ dx$
Then apply partial fraction decomposition: $\displaystyle \frac{3 - 2x}{(x-2)^2} = \frac{A}{x-2} + \frac{B}{(x-2)^2}$
Try it now.