Thread: comparing coefficients

Ok just quickly what happens in this case


A + B = 3
-2A - 2B = -2

Both terms disapear when I add them together.. what do i need to do to get the values of A and B??

2A +2B = 6
-2A -2B = -2

0 = 4

What was the original question?

Divide the second equation by -2 and we have:

Now think about this logically. How can two numbers add up to 3 and 1 at the same time?

I see...

I was doing partial fractions,

int (3-2x) / (x^2-4x+4)

int (3-2x) / (x-2)(x-2)

A(x-2)+B(x-2)

Numerator: (A+B)x + (-2A-2B)

I'm guessing I've done something wrong here..

You have to combine the linear factors in the denominator into a single power:

Then apply partial fraction decomposition:

Try it now.

Ah right I get it, thanks alot!!