x^3-x^2+2

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- Jan 13th 2009, 10:02 PMprincess_21factor this completely
x^3-x^2+2

- Jan 13th 2009, 10:15 PMADARSH
- Jan 13th 2009, 10:30 PMprincess_21
- Jan 13th 2009, 10:33 PMJhevon
he factored by grouping.

$\displaystyle x^3 + 1$ <--------sum of two cubes. goes to $\displaystyle (x + 1)(x^2 - x + 1)$

$\displaystyle 1 - x^2$ <--------difference of two squares. goes to $\displaystyle (1 - x)(1 + x)$

in the third step, he factored out the common factor, that is, $\displaystyle (x + 1)$ - Jan 13th 2009, 10:37 PMADARSH
- Jan 13th 2009, 10:39 PMprincess_21
- Jan 13th 2009, 10:44 PMprincess_21factor this completely
thanks.

- Jan 13th 2009, 10:49 PMADARSH
I hope this would help

x^3-x^2+2 can be written as

= x^3 +x^2 - 2 x^2 -2x +2x+2

=x^2(x+1)-2x(x+1)+2(x+1)

=(x^2-2x+2)(x+1)...(Clapping)

...I think you got it before this reply