# Math Help - help me please :)

1. ## help me please :)

A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is $9416 dollars. How much did he invest at each rate? 2. Originally Posted by asugirl87 A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is$9416 dollars. How much did he invest at each rate?
Solve using a linear equation where x is the amount invested in the higher yeilding account. Solve for x

.06 (2x) + .10x = 9416
.12x +.10x = 9416
.22x = 9416
x = 42800

So he invests $42800 in the higher yeilding account, while investing 2x =$85600 in the other account.

Check.

3. ohh ok i got it now!
thank you!!