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Math Help - help me please :)

  1. #1
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    help me please :)

    A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is $9416 dollars. How much did he invest at each rate?
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  2. #2
    Senior Member MacstersUndead's Avatar
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    Quote Originally Posted by asugirl87 View Post
    A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is $9416 dollars. How much did he invest at each rate?
    Solve using a linear equation where x is the amount invested in the higher yeilding account. Solve for x

    .06 (2x) + .10x = 9416
    .12x +.10x = 9416
    .22x = 9416
    x = 42800

    So he invests $42800 in the higher yeilding account, while investing 2x = $85600 in the other account.

    Check.
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  3. #3
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    ohh ok i got it now!
    thank you!!
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