Hey
4X+31X-8=(31+4)X-8=35X-8
Now you can solve the equation 35X-8=0, can't you ? OO
Why are you looking for a trinomial ?
Hey guys... I am just finishing up my unit, and I had a question that I am stuck on..
Here it is:
Solve each of the following exponential equations:
b) 4(2^x) + 31 (2^x) - 8 = 0
So, I figure that I can replace (2^x) with just x, and then I would solve it like a complex trinomial.. However, it would then be 4x+31x -8, and I need it to be 4x^2 in order to do that. How am I supposed to solve this?
THanks
Thanks guys!
Masters, I am using your method, and I know how to solve it..
When I am writing it down (just asking cause this is a question that will be marked), I just solve this by changing
to
http://s180.photobucket.com/albums/x...=logquest3.jpg
I am sorry, I do have a rather basic grasp of logs... I am just wondering, how would I show my work to completion using your method of
Because I would just transform this into the diagram I showed above
The original question was correct. You are also correct earboth.. I just didn't know when and when not to use the substitution. The one and only example for the 'substitution' (my book is very limited with examples, and the explaining of the examples), looks the way that your question looked earboth'