# Thread: How to foil this equation...

1. ## How to foil this equation...

4
[ v(2x+2) - v(x-3)][ v(2x+2) - v(x-3)] = 4

*By the way , that v symbol means SQuare root. CAn someplease walk me through this process.

2. $(\sqrt{a} - \sqrt{b})^2 = a - 2\sqrt{ab} + b$

3. Originally Posted by jonnyboy17
4
[ v(2x+2) - v(x-3)][ v(2x+2) - v(x-3)] = 4

*By the way , that v symbol means SQuare root. CAn someplease walk me through this process.
Both terms in brackets are identical, so we can write this as:

$(\sqrt{2x+2} - \sqrt{x-3})^2 = 4$

And we know that $(a+b)^2 = a^2+2ab+b^2$

Hence $(\sqrt{2x+2})^2 - 2\sqrt{x-3}\sqrt{2x+2}+(\sqrt{x-3})^2 = 4$

Now for the middle term use the rule $\sqrt{a}\sqrt{b} =\sqrt{ab}$, and for the first and last terms use $\sqrt{a}^2 = a$, which gives:

$2x+2 - 2\sqrt{(x-3)(2x+2)}+x-3 = 4$

Now you have to use foil on the term INSIDE the square root. Can you solve from here?