yes.

There are a lot of different method to solve such a system of equations. I'll show you the substitution method:

From the first equation you get: x = 5-3y

Plug in this value into the 2nd equation: 3(5-3y)-y=5

Expand to 15-9y-y=5

you get 15 -10y = 5. Thus -10y = -10. Therefore y = 1

Re-substitute x = 5-3(1) = 2

If you use that 4x = 2*2x then your 2nd equation becomes:

3y = 1+2*(3y-2). Expand

3y = 1+6y-4

-3y = -3. therefore y = 1. Re-substitute 2x = 3-2. So x = 1/2

uff, I need a break. Next explanations will come soon!

Promised