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Math Help - Yet another indices thread

  1. #1
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    Dec 2008
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    Yet another indices thread

    Sorry, I just repeatedly confuse myself.

    So for this question.. Solve the following equation:

    3^{4x}=27^{x+3}

    Thanks in advance.
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  2. #2
    MHF Contributor
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    Sep 2008
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    West Malaysia
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    Re :

    Quote Originally Posted by ns2583 View Post
    Sorry, I just repeatedly confuse myself.

    So for this question.. Solve the following equation:

    3^{4x}=27^{x+3}

    Thanks in advance.

    27=3^3

    3^{4x}=3^{3(x+3)}

    hope u understand what i did .
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  3. #3
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    Completely, thank you!
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