Sorry, I just repeatedly confuse myself. So for this question.. Solve the following equation: $\displaystyle 3^{4x}=27^{x+3}$ Thanks in advance.
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Originally Posted by ns2583 Sorry, I just repeatedly confuse myself. So for this question.. Solve the following equation: $\displaystyle 3^{4x}=27^{x+3}$ Thanks in advance. $\displaystyle 27=3^3$ $\displaystyle 3^{4x}=3^{3(x+3)}$ hope u understand what i did .
Completely, thank you!
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