Sorry, I just repeatedly confuse myself.

So for this question.. Solve the following equation:

$\displaystyle 3^{4x}=27^{x+3}$

2. Re :

Originally Posted by ns2583
Sorry, I just repeatedly confuse myself.

So for this question.. Solve the following equation:

$\displaystyle 3^{4x}=27^{x+3}$

$\displaystyle 27=3^3$
$\displaystyle 3^{4x}=3^{3(x+3)}$