Sorry, I just repeatedly confuse myself.

So for this question..Solve the following equation:

$\displaystyle 3^{4x}=27^{x+3}$

Thanks in advance.

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- Jan 12th 2009, 06:22 AMns2583Yet another indices thread
Sorry, I just repeatedly confuse myself.

So for this question..**Solve the following equation:**

$\displaystyle 3^{4x}=27^{x+3}$

Thanks in advance. - Jan 12th 2009, 06:24 AMmathaddictRe :
- Jan 12th 2009, 06:25 AMns2583
Completely, thank you!