Yet another indices thread

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January 12th 2009, 06:22 AM
ns2583

Yet another indices thread

Sorry, I just repeatedly confuse myself.

So for this question.. Solve the following equation:

$3^{4x}=27^{x+3}$

Thanks in advance.
January 12th 2009, 06:24 AM
mathaddict

Re :

Quote:

Originally Posted by ns2583

Sorry, I just repeatedly confuse myself.

So for this question.. Solve the following equation:

$3^{4x}=27^{x+3}$

Thanks in advance.

$27=3^3$

$3^{4x}=3^{3(x+3)}$

hope u understand what i did .
January 12th 2009, 06:25 AM
ns2583

Completely, thank you!

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