• January 12th 2009, 07:22 AM
ns2583
Sorry, I just repeatedly confuse myself.

So for this question.. Solve the following equation:

$3^{4x}=27^{x+3}$

• January 12th 2009, 07:24 AM
Re :
Quote:

Originally Posted by ns2583
Sorry, I just repeatedly confuse myself.

So for this question.. Solve the following equation:

$3^{4x}=27^{x+3}$

$27=3^3$

$3^{4x}=3^{3(x+3)}$

hope u understand what i did .
• January 12th 2009, 07:25 AM
ns2583
Completely, thank you!