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Math Help - Another Indices Question

  1. #1
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    Another Indices Question

    Hi, sorry and thanks in advance to anyone who can help me out.

    The question is to simplify it, giving my answer in index form.

    Cube root of
    (8a^-3)/(64b^-3)
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  2. #2
    MHF Contributor
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    Talking

    Quote Originally Posted by ns2583 View Post
    Cube root of

    (8a^-3)/(64b^-3)
    Is your expression the following?

    . . . . . \sqrt[3]{\frac{8a^{-3}}{64b^{-3}}}

    What were the instructions?

    Thank you!
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  3. #3
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    Yep, that's right.
    The question is to simplify it, giving myu answer in index form.
    (Sorry for forgetting to mention that)
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  4. #4
    MHF Contributor
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    Quote Originally Posted by ns2583 View Post
    The question is to simplify it...
    You've simplified the fraction 8/64, and used the exponent rules you've learned to move the a and b variables to get positive exponents. Then you used the fact that cubes and cube-roots are "opposite" processes which, just like addition and subtraction, "undo" each other. And... then what? Where are you stuck?

    Please be complete. Thank you!
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