# lost

• January 11th 2009, 02:38 PM
crazy101
lost
totally lost on this problem... any suggestions on how to even start it is greatly appreciated ...

Solve the absolute value equation

l 1/2x + 2 l = l 3/4x-2 l

both equations are in absolute terms with i guess you could say,both x's are next to the fractions. I hope i made that easy to understand

thanks for all the help!
• January 11th 2009, 03:01 PM
skeeter
$\left| \frac{x}{2} + 2 \right| = \left| \frac{3x}{4} - 2 \right|$

square both sides ...

$\frac{x^2}{4} + 2x + 4 = \frac{9x^2}{16} - 3x + 4$

$0 = \frac{5x^2}{16} - 5x$

$0 = 5x\left(\frac{x}{16} - 1\right)$

$x = 0$ ... $x = 16$