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Math Help - Simplifying this expression:

  1. #1
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    Simplifying this expression:

    Hey guys, I'm having a hard time trying to figure out how to simplify this:

    *Problem is attached* If you can't use that it's here:
    6x(2x+1)^1/4 (x^2+1)^2 + .5(2x+1)^-3/4 (x^2+1)^3

    I need a start, and I'm assuming it's with the exponents but I can't figure it out for my life.

    Thanks for any help guys.
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  2. #2
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    Simplifying

    Hello Kaln0s
    Quote Originally Posted by Kaln0s View Post
    Hey guys, I'm having a hard time trying to figure out how to simplify this:

    *Problem is attached* If you can't use that it's here:
    6x(2x+1)^1/4 (x^2+1)^2 + .5(2x+1)^-3/4 (x^2+1)^3

    I need a start, and I'm assuming it's with the exponents but I can't figure it out for my life.

    Thanks for any help guys.
    Write the expression as:

    6x(2x+1)^\frac{1}{4} (x^2+1)^2 + \frac{.5 (x^2+1)^3}{(2x+1)^\frac{3}{4}}

    Then write it all over a common denominator:

    \frac{6x(2x+1) (x^2+1)^2 + .5 (x^2+1)^3}{(2x+1)^\frac{3}{4}} (Can you see how I've done that?)

    Don't multiply out the brackets - instead, take out a common factor (x^2+1)^2. Can you take it from here?

    Grandad
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  3. #3
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    Quote Originally Posted by Grandad View Post
    Hello Kaln0s
    Write the expression as:

    6x(2x+1)^\frac{1}{4} (x^2+1)^2 + \frac{.5 (x^2+1)^3}{(2x+1)^\frac{3}{4}}

    Then write it all over a common denominator:

    \frac{6x(2x+1) (x^2+1)^2 + .5 (x^2+1)^3}{(2x+1)^\frac{3}{4}} (Can you see how I've done that?)

    Don't multiply out the brackets - instead, take out a common factor (x^2+1)^2. Can you take it from here?

    Grandad
    What happened to the 1/4? Out of curiosity. I'm still kindof confused? Thanks for the help though. ^_^;
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  4. #4
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    Simplifying

    Hello Kaln0s
    Quote Originally Posted by Kaln0s View Post
    What happened to the 1/4? Out of curiosity. I'm still kindof confused? Thanks for the help though. ^_^;
    6x(2x+1)^\frac{1}{4} (x^2+1)^2 = \frac{6x(2x+1)^\frac{1}{4} (x^2+1)^2 \times (2x+1)^\frac{3}{4}}{(2x+1)^\frac{3}{4}}

    Then use the fact that (2x+1)^\frac{1}{4} \times (2x+1)^\frac{3}{4} = (2x+1)^{\frac{1}{4}+\frac{3}{4}} = (2x+1)^1

    Can you see that OK?

    Grandad
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