# Math Help - hw help

1. ## hw help

I'm having trouble figuring out a math problem.

1. x2(sqaured) + 12 =-7x

2. -6x - 2 = (3x + 1)2(sqaured)

My first instinct was to factor both. Not sure if this was the right approach. Please any advice or links to similar problems to help solve would help a lot

2. Originally Posted by Stump101
I'm having trouble figuring out a math problem.

1. x2(sqaured) + 12 =-7x

2. -6x - 2 = (3x + 1)2(sqaured)

My first instinct was to factor both. Not sure if this was the right approach. Please any advice or links to similar problems to help solve would help a lot

1. $x^2 + 12 = -7x$

$x^2 + 7x + 12 = 0$

$(x + 3)(x + 4) = 0$

$x + 3 = 0$ or $x + 4 = 0$

$x = -3$ or $x = -4$.

2. $-6x - 2 = (3x + 1)^2$

$-2(3x + 1) = (3x + 1)^2$

$0 = (3x + 1)^2 + 2(3x + 1)$

$0 = (3x + 1)(3x + 1 + 2)$

$0 = (3x + 1)(3x + 3)$

$0 = 3(3x + 1)(x + 1)$

So $3x + 1 = 0$ or $x + 1 = 0$

$x = -\frac{1}{3}$ or $x = -1$.