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Thread: hw help

  1. #1
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    hw help

    I'm having trouble figuring out a math problem.

    1. x2(sqaured) + 12 =-7x

    2. -6x - 2 = (3x + 1)2(sqaured)

    My first instinct was to factor both. Not sure if this was the right approach. Please any advice or links to similar problems to help solve would help a lot

    thanks in advance!
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  2. #2
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    Quote Originally Posted by Stump101 View Post
    I'm having trouble figuring out a math problem.

    1. x2(sqaured) + 12 =-7x

    2. -6x - 2 = (3x + 1)2(sqaured)

    My first instinct was to factor both. Not sure if this was the right approach. Please any advice or links to similar problems to help solve would help a lot

    thanks in advance!
    1. $\displaystyle x^2 + 12 = -7x$

    $\displaystyle x^2 + 7x + 12 = 0$

    $\displaystyle (x + 3)(x + 4) = 0$

    $\displaystyle x + 3 = 0$ or $\displaystyle x + 4 = 0$

    $\displaystyle x = -3$ or $\displaystyle x = -4$.


    2. $\displaystyle -6x - 2 = (3x + 1)^2$

    $\displaystyle -2(3x + 1) = (3x + 1)^2$

    $\displaystyle 0 = (3x + 1)^2 + 2(3x + 1)$

    $\displaystyle 0 = (3x + 1)(3x + 1 + 2)$

    $\displaystyle 0 = (3x + 1)(3x + 3)$

    $\displaystyle 0 = 3(3x + 1)(x + 1)$

    So $\displaystyle 3x + 1 = 0$ or $\displaystyle x + 1 = 0$

    $\displaystyle x = -\frac{1}{3}$ or $\displaystyle x = -1$.
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