If a =2 +i then in the form of a+bi what does a^-1 equal
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Originally Posted by Rimas If a =2 +i then in the form of a+bi what does a^-1 equal It means the multiplicative inverse, $\displaystyle \frac{1}{2+i}\cdot \frac{2-i}{2-i}=\frac{2-i}{4+1}=\frac{2}{5}-i\frac{1}{5}$
What?
Originally Posted by Rimas What? I multiplied by the "conjugate" to clear the denominator from imaginary numbers. Note, I multiplied both the numerator and denominator. The meaning of $\displaystyle a^{-1}$ is definied as the inverse, meaning, $\displaystyle \frac{1}{2+i}$
This is one of my favorite questions. The multiplicative inverse of a complex number z is: $\displaystyle z^{ - 1} = \frac{{\overline z }}{{\left| z \right|^2 }}.$ Of course $\displaystyle z\not = 0+0i$
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