Solve for x: 3^(2x) - 5(3^x) = -6 Asap please some explanation would be appreciated thank you Edit: the correct answers are 1 and 0.631, but why and how?
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Originally Posted by incognito_301 Solve for x: 3^(2x) - 5(3^x) = -6 Asap please some explanation would be appreciated thank you Edit: the correct answers are 1 and 0.631, but why and how? Here's a hint: note that now let then we have that is, this is just a quadratic equation. you can solve for and then replace it with and then solve for
Originally Posted by incognito_301 Solve for x: 3^(2x) - 5(3^x) = -6 Asap please some explanation would be appreciated thank you Edit: the correct answers are 1 and 0.631, but why and how? It's a quadratic. Solve it.
Originally Posted by incognito_301 Solve for x: 3^(2x) - 5(3^x) = -6 Asap please [snip] I would have thought you would want someone more competent than a sap to help you. Fortunately you got that competent help. But I wouldn't make a habit of asking for a sap to help you .....
LOL a sap wow amazing forum! didnt believe you replied so fast. thanks. alright, so A = -1 and A = 6 then l and i dont get the correct answers (1 and 0.631).
Originally Posted by incognito_301 LOL a sap wow amazing forum! didnt believe you replied so fast. thanks. alright, so A = -1 and A = 6 then l and i dont get the correct answers (1 and 0.631). as i said, it is a +6 not -6. when you move -6 over the equal sign, it becomes positive. since you are adding 6 to both sides but other than that, your method is correct (by the way, log(-1) is not defined in the real numbers. you'd put "no solution" in that case)
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