Solve for x: 3^(2x) - 5(3^x) = -6
Asap please
some explanation would be appreciated
thank you
Edit: the correct answers are 1 and 0.631, but why and how?
Here's a hint: note that $\displaystyle 3^{2x} = (3^x)^2$
now let $\displaystyle y = 3^x$
then we have $\displaystyle y^2 - 5y = -6$
that is, $\displaystyle y^2 - 5y + 6 = 0$
this is just a quadratic equation. you can solve for $\displaystyle y$ and then replace it with $\displaystyle 3^x$ and then solve for $\displaystyle x$