i was wondering how do you remove the modulus of a function e.g. if you had modulus of y how do you find y.

i thought you would just do the inverse of (A^2+B^2)^0.5 but i was told this was wrong?? any help would be appreciated

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- Jan 10th 2009, 08:58 AMhmmmmmodulus
i was wondering how do you remove the modulus of a function e.g. if you had modulus of y how do you find y.

i thought you would just do the inverse of (A^2+B^2)^0.5 but i was told this was wrong?? any help would be appreciated - Jan 10th 2009, 11:22 PMGrandadMore information please
- Jan 11th 2009, 01:43 AMhmmmm
aorry it wasnt that great an explanation if you integrated 1/z dz=2x+4you would end up with ln|z|=x^2+4x+c then getting rid of the ln you would have

|z|=e^(x^2+4x+c) i was wondering how you would write this for z=?? - Jan 11th 2009, 02:00 AMMoo
Hello,

Since you talk about modulus, I assume that z is complex, then you can write , and this defined a value that exists.

Note that if z and z' are complex numbers, we have :

and

If you're talking about*absolute values*, and z is a real number, then you indeed have

So

Hence z can be equal to or

Also, don't forget the integration constant. - Jan 11th 2009, 02:01 AMmr fantastic
- Jan 11th 2009, 02:05 AMMoo
- Jan 11th 2009, 02:27 AMhmmmmthanks
thanks, if it is an absolute value is this always how you would remove the modulus?

- Jan 11th 2009, 02:29 AMMoo
- Jan 11th 2009, 03:54 AMmr fantastic
- Jan 11th 2009, 04:21 AMProve It
You missed a step, just for the benefit of the OP...

Let's just remember that if

then or .

This makes sense because the modulus is really the SIZE or LENGTH or MAGNITUDE of what is inside it.

So if we had, as above

we use the index law to get

So

But since is an arbitrary constant, so is . Therefore we could write is as another letter, say A.

So .

Make sense? - Jan 11th 2009, 04:27 AMhmmmm
thinik so, are you saying that as |z| is the magnitude we must do the inverse of what we did to get the magnitude?? this is what i origonally thought however i was told this was wrong by my teacher??

- Jan 11th 2009, 04:29 AMProve It
Yes that's correct in essentials.

I think your teacher is just getting a bit pedantic - technically speaking if you deal with mods you have to deal with conditions, but if dealing with integration you're assumed to already know this and so can do the "inverse modding" as you say. - Jan 11th 2009, 04:53 AMhmmmm
thanks alot