You can use A = ln(x)+ln(y) = ln(xy)
Then xy = e^A
y = e^A/x
Ok I'm not entirely sure if this is possible, but would like some verification either on whether it isn't possible and if it is possible then a solution or a nudge on what to do would be great.
I have the following equations
I need to find the intersection points for a value of A so I have
A = x + 2y
A = ln(x)+ln(y)
Now obviously I can only hope to get rid of one of the variables but I am looking for the answer in the form X = an equation involving only A and y = an equation involving only A is this possible, and if so what is it?
Thanks in advance