(root)x+y=11, x+(root)y=7
Can anyone help me to find the values of X and Y? Thanks.
$\displaystyle \sqrt(x) = 11-y $*
$\displaystyle x = 121 - 22y +y^2 $
$\displaystyle \sqrt(y) = 7-x $
$\displaystyle y = 49 - 14x +x^2 $
$\displaystyle 1444 - 1065 x + 272 x^2 - 28 x^3 + x^4 =0 $*
Try the factor of 1444 as roots. You should not search for a long time.
I keep thinking there must be a more elegant solution but this is one.