(root)x+y=11, x+(root)y=7

Can anyone help me to find the values of X and Y? Thanks.

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- Jan 9th 2009, 07:31 AMchequeSimultaenous Eq. with two unknowns
(root)x+y=11, x+(root)y=7

Can anyone help me to find the values of X and Y? Thanks. - Jan 9th 2009, 08:33 AMajj86Possible Solution
- Jan 9th 2009, 08:38 AMcheque
- Jan 9th 2009, 08:39 AMvincisonfire
$\displaystyle \sqrt(x) = 11-y $*

$\displaystyle x = 121 - 22y +y^2 $

$\displaystyle \sqrt(y) = 7-x $

$\displaystyle y = 49 - 14x +x^2 $

$\displaystyle 1444 - 1065 x + 272 x^2 - 28 x^3 + x^4 =0 $*

Try the factor of 1444 as roots. You should not search for a long time.

I keep thinking there must be a more elegant solution but this is one.