Hello, struck!
Solve: . I'll do it the Long Way . . .
Since both and can be positive or negative,
. . there are four cases to consider:
[1] Both positive: .
. . .Then we have: . . . . impossible
[2] Positivenegative: .
. . .But this means: . . . . impossible
[3] Negativepositive: .
. . .Then we have: .
[4] Negativenegative: .
. . .Then we have: . . . . always true.
The inequality is satisfied in cases [3] and [4]
The solution is: .
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
If we graph the two functions, we can "eyeball" the solution.
The graph of is a , vertex at (0,0). .[1]
The graph of . . is [1], moved one unit to the right. Code:
\
1* /
\ /
 \ /
 \ /
 \ /
 \ /
    +   *    
 1
The graph of . .is [1], moved one unit upward. Code:

\  /
\  /
\  /
\  /
\  /
\/
1*





    +       

Sketch them on the same coordinate system
. . and we can see the solotion: .