Thank you so much for your help with that one, I have one more if you don't mind, having trouble with this as well.
(2p-1)(p+3) + (7p+4)(p+3)
I know they both have the p + 3 in common but I don't know where to start. Thank you very much for your help.
(p + 3) ([2p - 1] + [7p + 4]) = (p + 3)(2p - 1 + 7p + 4)
= (p + 3)(9p + 3).
Since 3 is a commn factor or 9p + 3 you can write it as 3(3p + 1).
So you have (p + 3) 3(3p + 1) = 3(p + 3)(3p + 1)
since obviously you can change the order of things that you multiply together.