1. ## Grade 9 Math Help

Missed today's class due to being stuck sick in bed. I have a quiz tomorrow on Consecutive Integer Problems using fractions in the word problems. Can you help me with the following question? The larger of two consecutive odd integers is 4 less than 1/3 the smaller. Find the numbers.
Thanks

2. Originally Posted by anabanana
Missed today's class due to being stuck sick in bed. I have a quiz tomorrow on Consecutive Integer Problems using fractions in the word problems. Can you help me with the following question? The larger of two consecutive odd integers is 4 less than 1/3 the smaller. Find the numbers.
Thanks
Two consecutive odd integers always take the form $\displaystyle 2k+1,\ 2k+3$ for some integer $\displaystyle k$.

You are told that

$\displaystyle 2k+3=\frac{(2k+1)}{3} - 4$

Which you now solve for $\displaystyle k$, and hence for the two numbers (don't be supprised if one or both are negative)

.

3. ## Integers

Hello anabanana
Originally Posted by anabanana
Missed today's class due to being stuck sick in bed. I have a quiz tomorrow on Consecutive Integer Problems using fractions in the word problems. Can you help me with the following question? The larger of two consecutive odd integers is 4 less than 1/3 the smaller. Find the numbers.
Thanks
Suppose that the smaller odd integer is $\displaystyle n$; then the next larger one will be $\displaystyle (n+2)$.

So: $\displaystyle (n+2)$ is $\displaystyle 4$ less than $\displaystyle \frac{1}{3}$ of $\displaystyle n$.

In other words: $\displaystyle n+2 = \frac{1}{3}n - 4$

Add $\displaystyle 4$ to both sides; multiply both sides by $\displaystyle 3$; then ...?

Can you solve it now? (The answer is a negative odd integer.)