# Thread: Algebra Word Question (Linear Equations)

1. ## Algebra Word Question (Linear Equations)

Altogether 292 tickets were sold for a high school basketball game. An adult ticket costs $3. A student ticket costs$1. $470 in tickets were sold. Find the number of each type of ticket sold. (Solve by Elimination) Someone help me, I just don't know where to start. I have to solve it using the method of elimination. 2. Originally Posted by usmc123 Altogether 292 tickets were sold for a high school basketball game. An adult ticket costs$3. A student ticket costs $1.$470 in tickets were sold. Find the number of each type of ticket sold. (Solve by Elimination)

Let $a$ be the number of adult tickets sold
Let $s$ be the number of student tickets sold

Since each adult ticket costs $3, the money made form the adult tickets is $3a$ Since each student ticket costs$1, the money made form the student tickets is $s$

in total, 292 tickets were sold for \$470, so that we have

$a + s = 292$ ............(1)
$3a + s = 470$ ..........(2)

there are your simultaneous equations. you can solve the system using elimination. you want to find $a$ and $s$