# Thread: Algebra Word Question (Linear Equations)

1. ## Algebra Word Question (Linear Equations)

Altogether 292 tickets were sold for a high school basketball game. An adult ticket costs $3. A student ticket costs$1. $470 in tickets were sold. Find the number of each type of ticket sold. (Solve by Elimination) Someone help me, I just don't know where to start. I have to solve it using the method of elimination. 2. Originally Posted by usmc123 Altogether 292 tickets were sold for a high school basketball game. An adult ticket costs$3. A student ticket costs $1.$470 in tickets were sold. Find the number of each type of ticket sold. (Solve by Elimination)
Let $\displaystyle a$ be the number of adult tickets sold
Let $\displaystyle s$ be the number of student tickets sold
Since each adult ticket costs $3, the money made form the adult tickets is$\displaystyle 3a$Since each student ticket costs$1, the money made form the student tickets is $\displaystyle s$
in total, 292 tickets were sold for $470, so that we have$\displaystyle a + s = 292$............(1)$\displaystyle 3a + s = 470$..........(2) there are your simultaneous equations. you can solve the system using elimination. you want to find$\displaystyle a$and$\displaystyle s\$