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Math Help - Algebra Word Question (Linear Equations)

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    Algebra Word Question (Linear Equations)

    Altogether 292 tickets were sold for a high school basketball game. An adult ticket costs $3. A student ticket costs $1. $470 in tickets were sold. Find the number of each type of ticket sold. (Solve by Elimination)
    Someone help me, I just don't know where to start. I have to solve it using the method of elimination.
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by usmc123 View Post
    Altogether 292 tickets were sold for a high school basketball game. An adult ticket costs $3. A student ticket costs $1. $470 in tickets were sold. Find the number of each type of ticket sold. (Solve by Elimination)
    here's your start

    Let a be the number of adult tickets sold
    Let s be the number of student tickets sold

    Since each adult ticket costs $3, the money made form the adult tickets is 3a

    Since each student ticket costs $1, the money made form the student tickets is s

    in total, 292 tickets were sold for $470, so that we have

    a + s = 292 ............(1)
    3a + s = 470 ..........(2)

    there are your simultaneous equations. you can solve the system using elimination. you want to find a and s
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