Results 1 to 3 of 3

Math Help - 3 Part Inequality question

  1. #1
    Newbie
    Joined
    Dec 2008
    Posts
    11

    3 Part Inequality question

    It doesn't look too hard and probably isn't for you guys but I just cant seem to be able to get around it (the " / " represent fractions)

    Solve:
    -2 < x/2 < 1-2x/3

    I'm able to simplify it to :
    -12 < 3x < 6-4x

    But after that I'm pretty much stuck, main problem for me I think is that there's two X terms there and I don't know what to do with :\


    Thanks, hope I made sense
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Lord of certain Rings
    Isomorphism's Avatar
    Joined
    Dec 2007
    From
    IISc, Bangalore
    Posts
    1,465
    Thanks
    6
    Quote Originally Posted by Supaweak View Post
    It doesn't look too hard and probably isn't for you guys but I just cant seem to be able to get around it (the " / " represent fractions)

    Solve:
    -2 < x/2 < 1-2x/3

    I'm able to simplify it to :
    -12 < 3x < 6-4x

    But after that I'm pretty much stuck, main problem for me I think is that there's two X terms there and I don't know what to do with :\


    Thanks, hope I made sense
    -12 < 3x < 6-4x is same as saying -12 < 3x and 3x < 6-4x. But this means -4 < x and 7x < 6. Thus -4 < x and x < 6/7, which is the same as saying -4 < x < 6/7
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Dec 2008
    Posts
    11
    Thanks isomorphism! I get it now
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. prove part (b) of this integration inequality
    Posted in the Differential Geometry Forum
    Replies: 0
    Last Post: September 9th 2010, 01:42 AM
  2. Need help with the second part of this question.
    Posted in the Statistics Forum
    Replies: 1
    Last Post: February 12th 2010, 06:01 PM
  3. Replies: 25
    Last Post: January 15th 2010, 04:53 AM
  4. I bet you will not know this trig question part two
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: February 10th 2009, 12:06 PM
  5. Replies: 3
    Last Post: July 20th 2008, 06:24 AM

Search Tags


/mathhelpforum @mathhelpforum