Hello, sahip!

An interesting problem . . .

I had to baby-talk my way through it.

Let = orginal amount of water (gallons).A ship's hull was punctured and filled with water before being sealed off.

A pump removed water at a steady rate of 5 gallons per minute,

but after 75% of the water was removed, the pump slowed.

If the water was removed at an average rate of 4 gallons per minute,

at what rate was the remaining 25% of the water removed ?

Let = slower rate of pumping (gallons per minute).

The first 75% of the water was removed at 5 gallons per minute.

That is, gallons were removed at 5 gal/min.

. . This took: . minutes.

The last 25% of the water was removed at gallons per minute.

That is, gallons were removed at gal/min.

. . This took: . minutes.

The total time to empty the water was: . minutes.

Recap: They pumped gallons of water in minutes

. . . . . and the average rate was 4 gallons per minute.

There is our equation: .

Divide by

The last 25% of the water was pumped out at gallons per minute.