Give the usual ax^2 + bx + c form of the quadratic function which has a = 1, and has two zeros z = 3 + 2i and z' = 3 - 2i
I am really having probelms with this question and now have little time to solve it.
If $\displaystyle z = 3 + 2i $ is a root, then $\displaystyle (z-3-2i) $ is a factor.
If $\displaystyle z = 3 - 2i $ is a root, then $\displaystyle (z-3+2i) $ is a factor.
Hence you can say $\displaystyle z^2 + bz + c = (z-3+2i)(z-3-2i) $
If you multiply that out you'll be able to see what b and c are.