I have been given a question to expand and simplify this: (3+root6)(2-root3)
i managed to get it down to 6-3root3-3root2+2root6 but i cannot get it any further, help would be much appreciated.
PS sorry i could find a square root sign.
Hello, gustifo!
Ya done good!
Simplify: .$\displaystyle (3 + \sqrt{6})(2-\sqrt{3})$
$\displaystyle (3+\sqrt{6})(2 - \sqrt{3}) \;=\;(3)(2) + (3)(\text{-}\sqrt{3}) + (\sqrt{6})(2) + (\sqrt{6})(\text{-}\sqrt{3})$
. . $\displaystyle = \;6 - 3\sqrt{3} - 2\sqrt{6} - \sqrt{18} $
But $\displaystyle \sqrt{18} \:=\:\sqrt{(9)(2)} \:=\:\sqrt{9}\,\sqrt{2} \:=\:3\sqrt{2}$
. . Therefore: .$\displaystyle 6 - 3\sqrt{3} - 2\sqrt{6} - 3\sqrt{2}$
And that's as far as we can go . . .
Edit: Too slow again . . . *sigh*