# Recursive Formula

• January 4th 2009, 06:11 PM
casey_k
Recursive Formula
If t1 = 6, t2 = 4, t3 = 2 and

$

t_n = (t_{n-3} + t_{n-2}) \cdot t_{n-1}
$

Find t7.
• January 4th 2009, 06:15 PM
Chris L T521
Quote:

Originally Posted by casey_k
If t1 = 6, t2 = 4, t3 = 2 and

$

t_n = (t_{n-3} + t_{n-2}) \cdot t_{n-1}
$

Find t7.

Its a matter of applying the recursive forumula.

When $n=4$, you have

$t_4=(t_1+t_2)\cdot t_3=(6+4)\cdot 2=24$

When $n=5$, you have

$t_5=(t_2+t_3)\cdot t_4=(4+2)\cdot 24=144$

Can you continue on with this process?