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Math Help - Advanced functions review question help !

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    Exclamation Advanced functions review question help !

    can anyone explain how to solve this question for x ?

    |x-1|+2x-8=0
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    Quote Originally Posted by lola_11 View Post
    can anyone explain how to solve this question for x ?

    |x-1|+2x-8=0
    |x - 1| = x -1 if x > 1 and 1 - x if x \leq 1. So solve each of the following cases:

    Case 1: x - 1 + 2x - 8 = 0 and x > 1.

    Case 2: 1 - x + 2x - 8 = 0 and x \leq 1.
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