# Thread: Advanced functions review question help !

1. ## Advanced functions review question help !

can anyone explain how to solve this question for x ?

|x-1|+2x-8=0

2. Originally Posted by lola_11
can anyone explain how to solve this question for x ?

|x-1|+2x-8=0
$|x - 1| = x -1$ if $x > 1$ and $1 - x$ if $x \leq 1$. So solve each of the following cases:

Case 1: $x - 1 + 2x - 8 = 0$ and $x > 1$.

Case 2: $1 - x + 2x - 8 = 0$ and $x \leq 1$.