can anyone explain how to solve this question for x ?
|x-1|+2x-8=0
$\displaystyle |x - 1| = x -1$ if $\displaystyle x > 1$ and $\displaystyle 1 - x$ if $\displaystyle x \leq 1$. So solve each of the following cases:
Case 1: $\displaystyle x - 1 + 2x - 8 = 0$ and $\displaystyle x > 1$.
Case 2: $\displaystyle 1 - x + 2x - 8 = 0$ and $\displaystyle x \leq 1$.