# Advanced functions review question help !

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• January 4th 2009, 05:33 PM
lola_11
Advanced functions review question help !
can anyone explain how to solve this question for x ?

|x-1|+2x-8=0
• January 4th 2009, 05:38 PM
mr fantastic
Quote:

Originally Posted by lola_11
can anyone explain how to solve this question for x ?

|x-1|+2x-8=0

$|x - 1| = x -1$ if $x > 1$ and $1 - x$ if $x \leq 1$. So solve each of the following cases:

Case 1: $x - 1 + 2x - 8 = 0$ and $x > 1$.

Case 2: $1 - x + 2x - 8 = 0$ and $x \leq 1$.