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Math Help - algebra 2 help

  1. #1
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    algebra 2 help

    Could any one please explain to me how to solve them thanks =)


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  2. #2
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    Quote Originally Posted by Steven2 View Post
    Could any one please explain to me how to solve them thanks =)


    I'll help with Q2: y = \frac{x^2 - 4}{2x^2 + 5x - 12}.

    x -int: Apply the definition: Solve x^2 - 4 = 0.


    Vertical asymptote: Apply the definition: Solve 2x^2 + 5x - 12 = 0.


    Horizontal asymptote: Apply the definition and consider the limit as x \rightarrow \pm \infty.

    Two options:

    1. From polynomial long division y = \frac{x^2 - 4}{2x^2 + 5x - 12} = \frac{1}{2} - \frac{5x-4}{2(2x^2 + 5x - 12)}.

    2. y = \frac{x^2 - 4}{2x^2 + 5x - 12} = \frac{1 - \frac{4}{x^2}}{2 + \frac{5}{x} - \frac{12}{x^2}}.

    Either way,  y \rightarrow 2 ....
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  3. #3
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    Thanks for the response but could you help me factor the denominator.

    Example X^2-9x+18 factors out to (x-3)(X-6)


    Just cant seem to factor this problem.
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  4. #4
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    Quote Originally Posted by Steven2 View Post
    Thanks for the response but could you help me factor the denominator.

    Example X^2-9x+18 factors out to (x-3)(X-6)


    Just cant seem to factor this problem.
    2x^2 + 5x - 12 = (2x-3)(x+4).

    If you had trouble factorising then you should have tried solving the equation using the quadratic formula.
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